化简求值(1)2x^2y(-2xy^2)^3+(2xy)^3(-xy^2)^2,其中x=3,y=1/4
(2)(1/3xy)^2(xy(2x-y)-2x(xy-y^2)),其中x=-1又二分之一,y=-2
人气:262 ℃ 时间:2020-03-15 01:08:46
解答
(1)
2x^2y(-2xy^2)^3+(2xy)^3(-xy^2)^2
=-2x^2y(2xy^2)^3+(2xy)^3(xy^2)^2
=-16x^5y^7+8x^5y7
=-8x^5y^7
=-8*3^5*(1/4)^7
=-2*(3/4)^5
(2)
(1/3xy)^2(xy(2x-y)-2x(xy-y^2))
=(1/3xy)^2(xy(2x-y)-2xy(x-y))
=(1/3xy)^2(xy(2x-y-2x+2y))
=(1/3xy)^2(xy^2)
=(x^3y^4)/3
=(-27/8*16)/3
=-18
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