x2+3x+1=0,求x3+1/x3与x7+1/x7的值.
人气:194 ℃ 时间:2020-06-01 00:38:09
解答
x^2+3x+1=0,求x^3+1/x^3与x^7+1/x^7的x^2+3x+1=0 x不等于0两边同时除以xx+1/x=-3x^3+1/x^3=(x+1/x)(x^2-1+1/x^2)=3[(x+1/x)^2-3]=3*[(-3)^2-3]=18x^2+1/x^2=7平方x^4+2+1/x^4=49x^4+1/x^4=47x^7+1/x^7=(x^4+1/x^4)(x...
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