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如图,在△ABC中,∠ABC的平分线与∠ABC的外交平分线交于点D,若∠D=40°,则∠A=______.
人气:462 ℃ 时间:2019-09-23 13:59:37
解答
∵BD是∠ABC的平分线,∴∠DBC=12∠ABC,∵CD是△ABC的外角平分线,∴∠ACD=12(∠A+∠ABC),∵∠D+∠DBC+∠ACB+∠ACD=180°,即12∠ABC+∠ACB+12(∠A+∠ABC)=140°①,∠A+∠ABC+∠ACB=180°②,∴∠ABC+∠ACB=1...
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