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求函数f(x)=sin(4x+π/3)+cos(4x-π/6)的周期
人气:169 ℃ 时间:2020-02-04 03:24:04
解答
f(x)=sin(4x+π/3)+cos(4x-π/6)
=sin(4x-π/6+π/2)+cos(4x-π/6)
=cos(4x-π/6)+(4x-π/6)
=2cos(4x-π/6)-1+1
=cos(8x-π/3)+1

=>T=2π/8=π/4
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