x^2-6x+5, (y+2)(y+4)+1, -a^4b^4+8a^2b^2-16 这三提怎么进行因式分解_数学解答

x^2-6x+5, (y+2)(y+4)+1, -a^4b^4+8a^2b^2-16 这三提怎么进行因式分解

人气：372 ℃　时间：2020-04-06 06:01:26

解答

x^2-6x+5 ,=(x-5)(x-1)(y+2)(y+4)+1 ,=y^2+6y+8+1=y^2+6y+9=(y+3)^2-a^4b^4+8a^2b^2-16 =-(a^4b^4-8a^2b^2+16 )=-(a^2b^2-4 )^2=-[(ab-2)(ab+2)]^2=-(ab-2)^2(ab+2)^2