化简 sin17/8*π*cos7/4*π-cos7/8*π*sin3/4*π
人气:239 ℃ 时间:2020-02-04 10:46:38
解答
sin17π/8*cos7π/4-cos7π/8*sin3π/4=sin(2π+π/8)*cos(2π-π/4)-cos(π-π/8)*sin(π-π/4)=sinπ/8*cosπ/4-(-cosπ/8)*sinπ/4=sinπ/8*cosπ/4+cosπ/8*sinπ/4=sin(π/8+π/4)=sin(3π/4)=sin(π-π/4)=sin...
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