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数学
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用因式分解法解两道方程,(1)4x²-25=0 (2)(x+2)²-4=0
人气:317 ℃ 时间:2020-02-13 01:24:58
解答
(1)4x²-25=0
(2x+5)(2x-5)=0
2x+5=0或2x-5=0
x1=2.5,x2=-2.5
(2)(x+2)²-4=0
(x+2+2)(x+2-2)=0
x+4=0或x=0
x1=-4,x2=0
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