依题意,设向量a=(m,2)y=cos(2x+π/6)-2按向量a=(m,2)平移得到F': y=cos[2（x-m)+π/6]若 y=cos[2（x-m)+π/6]为奇函数cos[2（-x-m)+π/6]=-cos[2（x-m)+π/6]cos[-2x+(π/6-2m)]=-cos[2x+(π/6-2m)]∴cos2xcos(π/6-...