lim((sinx-ln(1+x^2)^1/2)/x^4) x->0求解 呵呵~
sin改成-cosx+1
人气:120 ℃ 时间:2020-05-22 01:41:58
解答
运用泰勒级数,把cosx和ln(1+x^2)展开
lim((-cosx+1-ln(1+x^2)^1/2)/x^4)
=lim[(-1+x^2/2-x^4/24+o(x^5)+1 -1/2(x^2-x^4/2+o(x^5)]/x^4
=5/24
推荐
猜你喜欢
- 已知圆C:x^2+y^2-2x+4y-4=0,斜率为1的直线l交C于A,B两点
- 若1mlpH=1的盐酸与100mlNaOH溶液混合后,溶液pH=7,则NaOH溶液的pH=11
- 把let's,a,game,chain,play(.)连词成句
- We____we chould study hard,A think all B see all C all think D all see
- The price_____,but I doubt whether it will remain so.A .went down
- please give me 至少六个音似词(英语)
- 细菌对人体有害吗?
- 两根同样长的钢管第1根用去5分之2米第2根用去5分之2拿一根用去的长一些