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求tant^3+1/sect^2的不定积分
人气:167 ℃ 时间:2020-05-19 01:06:50
解答

∫(tan³t+1)/(sec²t) dt
= ∫sin³t / cost dt +∫cos²tdt

=∫(1 - cos²t) sint / cost dt+1/2 ∫2cos²t-1+1dt

= - ∫(1 - cos²t) / cost dcost +sin2t/4+t/2
= - ∫1/cost dcost  + ∫cost dcost +sin2t/4+t/2

= - ln|cost| + cos²t/2 +sin2t/4+t/2+C

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