是不（2）证法一：连接CE,∵Rt△ABC≌Rt△ADE,∴AC=AE．∴∠ACE=∠AEC（等边对等角）．又∵Rt△ABC≌Rt△ADE,∴∠ACB=∠AED．∴∠ACE-∠ACB=∠AEC-∠AED．即∠BCE=∠DEC．∴CF=EF．证法二：∵Rt△ABC≌Rt△ADE,∴AC=...