将分式m/m^2-6m+9.-3M/2M^2-18.1/2m+6通分后,其分子之和是多少?_数学解答

将分式m/m^2-6m+9.-3M/2M^2-18.1/2m+6通分后,其分子之和是多少?

人气：357 ℃　时间：2020-03-20 16:45:11

解答

m/m^2-6m+9.-3M/2M^2-18+1/2m+6
=m/（m-3)^2-3m/2(m+3)(m-3)+1/2(m+3)
=9(m+1)/2（m-3)^2(m+3)
分子之和是=9(m+1)