已知△ABC中,
sinA(sinB+cosB)=sinC.
(I)求角A的大小;
(II)若BC=3,求△ABC周长的取值范围.
人气:182 ℃ 时间:2020-03-09 10:41:18
解答
(I)A+B+C=π得sinC=sin(A+B)代入已知条件得sinAsinB=3cosAsinB∵sinB≠0,由此得tanA=3,A=π3(II)由上可知:B+C=2π3,∴C=2π3-B由正弦定理得:AB+AC=2R(sinB+sinC)=23(sinB+sin(2π3-B))即得:AB+AC=23(32s...
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