[x/(3+x)]-[x/(2-x)]
=[x/(3+x)]+[x/(x-2)]
=x*{[1/(3+x)]+[1/(x-2)]}
=x*{(x-2+3+x)/[(x-2)*(x+3)]}
=x*(2x+1)/(x^2+x-6)
=(2x^2+x)/(x^2+x-6)