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(2-32a的4次方)/(4a的平方+1)/(2a+1)=
人气:206 ℃ 时间:2020-06-26 10:33:45
解答
(2-32a^4)/(4a^2+1)/(2a+1)
=2(1+4a^2)(1-4a^2)/(4a^2+1)/(2a+1)
=2(1+2a)(1-2a)/(2a+1)
=2-4a
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