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几道数学题,很快,急求
分解因式
(1)a^2-6ab+9b^2=
(2)16+24m+9m^2=
(3)a^2b^2-ab+1/4=
(4)49x^2-14xy+y^2=
(5)1/9+1/3x^2+1/4x^4=
(6)25a^2-20ab+4b^2=
分解因式,需过程
3a^2-12a^2+12a
-9-6ab-a^2b^2
1/4m^3n-1/4m^2n^2+1/16mn^3
a^4-2a^2+1
(x-2y)^2-12(x-2y)+36
(a+2b)^2+2(a+2b)(2a+b)+(2a+b)^2
人气:307 ℃ 时间:2020-05-09 01:33:13
解答
(1)(a-3b)^2
(2)(3m+4)^2
(3)(ab-1/2)^2
(4)(7x-y)^2
(5)(1/3+1/2 x^2)^2
(6)(5a-2b)^2
3a^2-12a^2+12a = -9a^2+12a= -3a(3a-4)
-9-6ab-a^2b^2 = -(a^2b^2+6ab+9)=-(ab+3)^2
1/4m^3n-1/4m^2n^2+1/16mn^3= 1/4mn(m^2-mn+1/4n^2)=1/4mn(m-1/2n)^2
a^4-2a^2+1 = (a^2-1)^2
(x-2y)^2-12(x-2y)+36 = (x-2y-6)^2
(a+2b)^2+2(a+2b)(2a+b)+(2a+b)^2 = (a+2b+2a+b)^2 = (3a+3b)^2=9(a+b)^2
基本上都是完全平方公式的运用~
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