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已知sin(x+π/6)=3分之根下3,怎么求sin^2(π/3-x)?
人气:212 ℃ 时间:2020-02-05 05:44:49
解答
sin^2(π/3-x)
=1-cos^2(π/3-x)
=1-sin^2[π/2-(π/3-x)]
=1-sin^^2(x+π/6)
=1-1/3
=2/3
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