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先化简,再求值:3a^2b-[2ab^2-2(ab-3/2a^2b)]+2ab.其中a、b满足|a+3b+1|+(2a+4)^2=0
人气:119 ℃ 时间:2019-10-23 07:03:07
解答
|a+3b+1|+(2a+4)^2=0
2a+4=0
a=-2
a+3b+1=0
3b-1=0
b=1/3
3a^2b-[2ab^2-2(ab-3/2a^2b)]+2ab
=3a²b-2ab²+2ab-3a²b+2ab
=4ab-2ab²
=4×(-2)×1/3-2×(-2)×1/9
=-8/3+4/9
=-20/9
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