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(1-3/x+2)÷x-1/x²+2x-x/x+1,其中x满足x²-x-1=0
人气:369 ℃ 时间:2020-06-01 23:13:53
解答
x²-x-1=0x²-x=1x²-x+1/4=1+1/4(x-1/2)²=5/4x-1/2=±√5/2x=1/2±√5/2=(1±√5)/2x²=(1±2√5+5)/2=(6±2√5)/2=3±√5x³=(1±3√5+15±5√5)/8=(16±8√5)/8=2±√5(1-3/x+2)÷x-1...
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