∵|x₁-1|+|x₂-2|+|x₃-3|+…+|x₂₀₀₂-2002|+|x₂₀₀₃-2003|=0，
∴x₁=1，x₂=2，x₃=3，…，x₂₀₀₂=2002，x₂₀₀₃=2003，
∴2x1−2x2−…−2x2002+2x2003
=2-2²-…-2²⁰⁰²+2²⁰⁰³
=2²⁰⁰³-2²⁰⁰²-…-2²+2
=2²⁰⁰²-2²⁰⁰¹…-2²+2
=2²⁰⁰¹-…-2²+2
…
=2²+2
=4+2
=6．
故代数式2x1−2x2−…−2x2002+2x2003的值为6．