因为x^2+4y^2=4所以设x=2cosa,y=sina a∈[0,2π)则M=4cos^2a+4sinacosa+4sin^2a+2cosa+2sina=4+4sinacosa+2(cosa+sina)令cosa+sina=t则t∈[-√2,√2]两边平方得:2sinacosa=t^2-1所以:M=2t^2+2t+2=2(t+1/2)^2+3/2所以...