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如图所示,AC平分∠DAB,AB>AD,CB=CD,CE⊥AB于E,

(1)求证:AB=AD+2EB;
(2)若AD=9,AB=21,BC=10,求AC的长.
人气:282 ℃ 时间:2020-03-05 17:59:44
解答
(1)证明:延长线段AD,过C作CF⊥AD交AD得延长线于F,∵AC为∠DAE的平分线,CE⊥AB,CF⊥AF,∴CE=CF,在Rt△CFD和Rt△CEB中CF=CECD=CB,∴Rt△CFD≌Rt△CEB(HL),∴FD=EB,又在Rt△CFA和Rt△CEA中CF=CEAC=AC...
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