此题用待定系数法.设：多项式分解为（3x+1)(2x-3)(cx+d)=(6x^2-7x-3)(cx+d)=6cx^3+(6d-7c)x^2-(7d+3c)x-3d根据题意（ax^3+bx^2-47x-15）得：6c=a ①6d-7c=b ②7d+3c=47 ③3d=15 ④ 得：d=5c=4a=24b=2所以：多项式ax^...