⑴由题意得,-π/2+2kπ≤2x-π/6≤π/2+2kπ-π/6+kπ≤x≤π/3+kπ故f(x)单调递增区间为[-π/6+kπ,π/3+kπ](k∈Z)⑵x∈[0,π/2]2x∈[0,π]2x-π/6∈[-π/6,5π/6]sin(2x-π/6)∈[-1/2,1]f(x)=2sin(2x-π/6)∈[-1,...