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(x^4+2x^2-3)/(x^2-3x+2) 当x→1时是无穷小量还是无穷大量
人气:300 ℃ 时间:2020-09-10 11:44:20
解答
(x^4+2x^2-3)/(x^2-3x+2) =(x²+3)(x²-1)/(x-2)(x-1)
=(x²+3)(x-1)(x+1)/(x-2)(x-1)
=(x²+3)(x+1)/(x-2)
当x→1时,
lim(x²+3)(x+1)/(x-2)=-8
所以他的极限为实数-8,不是无穷大或者无穷小
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