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1 [(x-2y)^3]^3÷[(2y-x)^2]^4=
2-(a^2b)^5÷(-a^2 b^3)=
3[(x-y)^2]^3÷[(y-x)^3]^2=
4(x^2y)6÷(x^2y)^3=
人气:437 ℃ 时间:2020-05-20 01:42:44
解答
1 [(x-2y)^3]^3÷[(2y-x)^2]^4= (x-2y)^9÷(2y-x)^8=(x-2y)^9÷(x-2y)^8=x-2y2 -(a^2*b)^5÷(-a^2 b^3)=-a^10*b^5÷(-a^2 b^3)=a^(10-2)*b^(5-3)=a^2*b^23 [(x-y)^2]^3÷[(y-x)^3]^2=(x-y)^6÷(y-x)^6=...
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