> 数学 >
△ABC中,若tanB•tanC=5,则
cosA
cos(B−C)
的值为______.
人气:133 ℃ 时间:2020-04-01 12:06:14
解答
由tanB•tanC=5,得
sinBsinC
cosBcosC
=5
,即sinBsinC=5cosBcosC,
所以
cosA
cos(B−C)
=
−cos(B+C)
cos(B−C)

=
sinBsinC−cosBcosC
cosBcosC+sinBsinC

=
5cosBcosC−cosBcosC
cosBcosC+5cosBcosC

=
2
3

故答案为:
2
3
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