(x³+1)(x²+1/x)^6其中(x²+1/x)^6的通项是C(6,i)*(x²)^(6-i)*(1/x)^i=C(6,i)*x^(12-3i)令12-3i=0得i=4所以常数项是C(6,4)=15令12-3i=3得i=3所以x³项是C(6,3)*x^(12-3*3)=20x³所以(x
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