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怎样分解2x^+3xy-2y^-x+8y-6
人气:334 ℃ 时间:2020-03-27 02:40:12
解答
两次十字相乘
2x^+3xy-2y^-x+8y-6
=(2x-y)(x+2y)+(-x+8y)-6
=[(2x-y)+3][(x+2y)-2]
=(2x-y+3)(x+2y-2)
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