设△ABC,正弦定理：a/sinA=b/sinB=c/sinC,已知∠B,AB=c,BC=a,求△ABC面积.S=1/2·acsinB.正弦定理：过A作AD⊥BC交BC于D,过B作BE⊥AC交AC于E,过C作CF⊥AB交AB于F,有AD=csinB,及AD=bsinC,∴csinB=bsinC,得b/sinB=c/sin...