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x的平方+x分之1+x的二次方+3x+2分之1+x的平方+5+6x分之1+x的二次方+7x+12分之1
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人气:449 ℃ 时间:2020-04-02 21:47:32
解答
=1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)
=1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)
=1/x-1/(x+4)
=(x+4-x)/x(x+4)
=4/(x²+4x)
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