f(x)=√3sin(2x＋π/6)＋cos(2x＋π/6)
=2sin[(2x＋π/6)＋(π/6)]
=2sin(2x＋π/3)
因为x∈[0,π/2],则：
2x＋π/3∈[π/3,4π/3]
得：sin(2x＋π/3)∈[－√3/2,1]
则：y∈[－√3,2]