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求sin(-1200°)×cos1290°+cos9-1020°)×sin(-1500°)+tan945°
人气:147 ℃ 时间:2020-06-19 19:05:21
解答
sin(-1200°)×cos1290°+cos(-1020°)×sin(-1500°)+tan945°
=sin(1440-1200)×cos(1080+210)+cos(1080-60)×sin(-1440-60)+tan(720+225)
=sin240°×cos210°+cos60°×sin(-60°)+tan225°
=sin60°×cos30°-cos60sin60°+tan45°
=3/4-√3/4+1
=7/4-√3/4
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