> 数学 >
9+log√2 27)(log27 4+log3√3 8)
人气:138 ℃ 时间:2020-04-19 20:46:16
解答
(log8 9+log√2 27)(log27 4+log3√3 8)
=(2/3log2 3+6log2 3)(2/3log32+2log32)
=20/3log2 3*8/3log32
=160/9那个3√3是3次根号=(2/3log2 3+6log2 3)(2/3log32+9log32)=20/3log2 3*29/3log32=580/9
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版