△ABC内角所对的边分别是a b c,asinAsinB+bcos²A=根号二a则b/a=?
人气：239 ℃ 时间：2019-11-04 14:11:24
解答
asinAsinB+bcos²A=√2a
正弦定理
sin²AsinB+sinBcos²A=√2sinA
sinB(sin²A+cos²A)=√2sinA
sinB=√2sinA
正弦定理
b=√2a
∴b/a=√2
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