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已知函数f(x=sinx+cosx)²+cos2x,求f(π/4)的值和f(x)的递增区间
人气:437 ℃ 时间:2020-04-10 13:34:26
解答
f(x)=(sinx+cosx)²+cos2x
=sin²x+cos²x+2sinxcosx+cos2x
=1+sin2x+cos2x
=1+√2sin(2x+π/4)
f(π/4)=1+1+0=2
f(x)的递增区间
2Kπ-π/2≤2x+π/4≤2K+π/2 ,K∈Z
Kπ-3π/8≤x≤Kπ+π/8 ,K∈Z
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