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已知x的负二次方+1=a(a是常数),则a²-2ax的负三次方+x的负六次方=?
人气:162 ℃ 时间:2019-08-20 04:00:38
解答
∵x^(-2)+1=a ∴x^(-2)=a -1∵x^(-6)+1=[x^(-2)+1][x^(-4)-x^(-2)+1]=(a-1+1)[(a-1)²-(a-1)+1]=a(a²-3a+3)∴x^(-6)=a³-3a²+3a-1=(a-1)³∴x^(-3)=(a-1)^(3/2)∴...
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