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lim x →2 (2/2x-x^2 +1/x^2-3x+2)求极限
人气:252 ℃ 时间:2019-10-27 05:18:53
解答
原式=lim[-2/x(x-2)+1/(x-1)(x-2)]
=lim[(-2x+2+x)/x(x-1)(x-2)]
=lim[-(x-2)/x(x-1)(x-2)]
==lim[(-1/x(x-1)]
=-1/2*1
=-1/2
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