已知f(x)=ax^5+bx^3+cx+7,且f(-7)=17,求f(7)_数学解答

已知f(x)=ax^5+bx^3+cx+7,且f(-7)=17,求f(7)

人气：319 ℃　时间：2020-06-27 19:37:45

解答

令g(x)=ax^5+bx^3+cx
g(x)是奇函数所以g(x)=-g(-x)
f(x)=g(x)+7
f(-7)=g(-7)+7=17
g(-7)=10
g(7)=-g(-7)=-10
f(7)=g(7)+7=-10+7=-3