f(x)=ax^5+bx^3+cx+7,f(-2011)=-17,则f(2011)=
人气:283 ℃ 时间:2020-06-28 02:25:39
解答
f(x)=ax^5+bx^3+cx+7
f(-2011)+f(2011)=7+7=14
f(-2011)=-17
f(2011)=14-(-17)=31
推荐
- 已知f(x)=ax^5+bx^3+cx+7,且f(-7)=17,求f(7)
- 已知x=1时,ax^5+bx^3-cx+3的值为10,那么x=-1时,ax^5+bx^3-cx+17值
- 若f(x)=ax五次方+bx三次方+cx+7且f(-7)=-17则f(7)=
- 知f(x)=ax+bx+cx+7,且f(-7)=17,f(-7)=17,求f(7).请热心的网友给出详细的步骤.
- 当x=2011时,代数式ax^5+bx^3+cx-29的值为2011;当x=-2011时,代数式ax^5+bx^3+cx-29的值为多少?
- The room is largh enough for us to live(加不加in)?
- However,I do not know how to retain the helpless是什么意思
- 组织的层次和管理幅度的关系是什么
猜你喜欢