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4y²-4y/y²-2y+1÷(y+1/y-1-y-1/y+1)÷(3y+3)
人气:411 ℃ 时间:2020-06-26 18:52:32
解答
4y²-4y/y²-2y+1÷(y+1/y-1-y-1/y+1)÷(3y+3)
=4y(y-1)/y(y-2)÷【(y+1)²-(y-1)²】/(y+1)(y-1)÷3(y+1)
=4(y-1)²/3(y-2)÷4y
=(y-1)²/3y(y-2)
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