已知sin(π-x)-cos(π-x)=√2/3 (π/2
(2)(sin(2π-x))^3+(cos(2π-x))的值
人气:359 ℃ 时间:2019-10-15 08:20:03
解答
sin(π-x)-cos(π-x)=√2/3
sinx+cosx=√2/3(利用诱导公式,奇变偶不变,符号看限象)
(sinx+cosx)^2=(√2/3)^2=4/9=sinx^2+sinx^2+cosx^2+cosx^2
又sinx^2+cosx^2=1
所以2sinxcosx=-5/9
π/2
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