> 数学 >
已知x1 x2 是一元二次方程x平方+3x+1=0的两个实数根,则x1三次方+8X2+20=
人气:416 ℃ 时间:2019-08-18 18:02:01
解答
x1三次方+8X2+20
=x1³+3x1²+x1+8x2+20-3x1²-x1
=x1(x1²+3x1+1)+8x2+20-3x1²-x1 ………………x1²+3x1+1=0
=8x2+20-3x1²-x1
=-3x1²-9x1+8x1+8x2+20 …………………………3x1²+9x1=-3
=-3+8(x1+x2)+20 …………………………X1+X2=-3
=-3+8*(-3)+20
=-7
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版