已知x1 x2 是一元二次方程x平方+3x+1=0的两个实数根,则x1三次方+8X2+20=
人气:269 ℃ 时间:2019-08-18 18:02:01
解答
x1三次方+8X2+20
=x1³+3x1²+x1+8x2+20-3x1²-x1
=x1(x1²+3x1+1)+8x2+20-3x1²-x1 ………………x1²+3x1+1=0
=8x2+20-3x1²-x1
=-3x1²-9x1+8x1+8x2+20 …………………………3x1²+9x1=-3
=-3+8(x1+x2)+20 …………………………X1+X2=-3
=-3+8*(-3)+20
=-7
推荐
猜你喜欢
- Did you have anything for breakfast?
- 若2的x+4次方乘以3的x+4次方=6的2x-1的次方,求x的值
- 口里面加子怎么念
- so excited so exciting用法上区别
- 向两个相同的容器中注入同深度的水和酒精,如图甲,若向两个容器中分别放入相同的物体,如图乙.设液体对容器底部压强为P,则
- He doesn't work as careful as I.he doesn't work as carefully as I.请问哪一句是对的,为什么,
- 甲乙丙三人同时从A地出发去100米外的B地.甲丙以25千米每时的乘车的速度,乙以5千米每时的
- 一块长为L,质量均匀分布的木板A平放在桌面上,木板A右端与桌面相齐,在版有段施一水平力使F离开桌面三分