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化简SINX-根号3COSX
人气:452 ℃ 时间:2020-03-19 10:11:54
解答
sinx-√3cosx
=2[(1/2)sinx-(√3/2)cosx]
=2[sinxcos(π/3)-cosxsin(π/3)]
=2sin(x- π/3)
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