ax^2-(a+1)x＋1＜0a=0时,ax^2-(a+1)x＋1=-x+11a≠0时,令ax^2-(a+1)x＋1=0则判别式△=[-(a+1)]^2-4*a*1=(a-1)^2≥0因此x1=[(a+1)+√(△)]/(2a)=(a+1+/a-1/)/(2a)x2=[(a+1)-√(△)]/(2a)=(a+1-/a-1/)/(2a)a...