∵a，b∈R+，且满足log4(2a+b)＝log2ab=log4ab，∴2a+b=ab，两边同除以ab，得1a+2b=1，∵a，b∈R+，∴8a+b=（8a+b）（1a+2b）=8+ba+16ab+2≥10+2ba•16ab=18，当且仅当ba＝16ab，即a=32，b=6时，8a+b取最小值18．故...