x2-2x+ (k2-6k+13)=0
x2-2x+ (k-3)²+4=0
（x-1)²+ (k-3)²+3=0
（x-1)²≥0
(k-3)²≥0
无解不好意思，漏了1/4题目应该是x2-2x+ 1/4(k2-6k+13)=0x2-2x+0.25 (k2-6k+13)=0x2-2x+0.25 (k-3)²+0.025×4=0（x-1)²+0.25 (k-3)²=0因为（x-1)²≥00.25(k-3)²≥0所以x-1=0并且k-3=0x=1,k=3所以m=10.025×4看不懂1/4就是0.25上面写错了