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tanx=1/7,tany=1/3,且x,y都是锐角,则2x+y=
人气:375 ℃ 时间:2020-06-07 19:05:32
解答
tanx = 1/7,tany = 1/3tan2x = 2tanx/(1-(tanx)^2)= (2/7) / (48/49)= 7/24tan( 2x+y)= (tan2x + tany)/(1-tan2xtany)= (7/24 + 1/3) /(1- (7/24)/3)= (15/24)/ (65/72)= (5/8)(72/65)= 9/132x+y = arctan(9/13)
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