(b-a)x^2+(a-b)x-(a+b)>0
x=1/2+√[5b^2-3a^2-2ab]/2(b-a)
0<√[5b^2-3a^2-2ab]/2(b-a)<1/2
b>a且5b^2-3a^2-2ab<(b-a)^2
4b^2-2a^2<0
4b^2<2a^2
b<-(1/2)a
a取-4,0
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