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将代数式x3+(2a+1)x2+(a2+2a-1)x+(a2-1)分解因式,得______.
人气:291 ℃ 时间:2020-04-17 17:11:22
解答
xg+(2人+1)x2+(人2+2人-1)x+(人2-1)
=xg+(2人+1)x2+(人2+2人)x-x+(人2-1)
=(xg-x)+[(2人+1)x2+(人2+2人)x+(人2-1)]
=x(x2-1)+[(2人+1)x+人2-1](x+1)
=x(x+1)(x-1)+[(2人+1)x+人2-1](x+1)
=(x+1)[x(x-1)+(2人+1)x+人2-1]
=(x+1)[x2-x+2人x+x+人2-1]
=(x+1)(x2+2人x+人2-1)
=(x+1)[(x+人)2-1]
=(x+1)(x+人+1)(x+人-1)
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